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sirinivas
Sep 13, 2010, 11:06 PM
find the probability that a non-leap year should have 53 saturdays?

Alty
Sep 13, 2010, 11:20 PM
Please see this announcement.

https://www.askmehelpdesk.com/math-sciences/announcement-font-color-ff0000-u-b-read-first-expectations-homework-help-board-b-u-font.html

Thanks.

Unknown008
Sep 14, 2010, 09:06 AM
Give us what you have tried so far. You should know what a leap year is. You should know how to find a specific probability too...

Then, find the number of different leap years with 53 Saturdays, and try to find out how many different leap years there can be.

Post what you get! :)

BillRussell
Sep 30, 2010, 11:55 AM
There are 365 days in a year, which is 52 weeks and 1 day. So the probability is 1/7.