View Full Version : What is the equilibrium expression for the following reaction: CO (g) + 3 H2 (g) CH4
Ochigun
Jul 28, 2010, 06:55 AM
A.)[ch4][h2o]/[co][h2]3
b.)[co][h2]3/[ch4][h2o]
c.)[h2o][h2]3/[ch4][co]
Ochigun
Jul 28, 2010, 07:00 AM
A.)[CO2][ZnO]/[ZnCO3]
B.)[CO2]
C.)[CO2]/[ZnCO3]
Ochigun
Jul 28, 2010, 07:21 AM
A.)is homogenous
B.)is at equilibrium under any condition
C.)is heterogeneous
Curlyben
Jul 28, 2010, 07:22 AM
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Unknown008
Jul 28, 2010, 12:03 PM
I'll give you an example of the equilibrium expression for another equation.
2HI (g) \rightleftharpoons H_2 (g) + I_2 (s)
K_p = \frac{(P_{H_2})(P_{I_2})}{(P_{HI})^2}
But since I_2 is a solid, then, P_(I2) = 1
Thus;
K_p = \frac{(P_{H_2})}{(P_{HI})^2}
HCOOH (aq) \rightleftharpoons HCOO^- (aq)+ H^+ (aq)
K_c = \frac{[HCOO^-][H^+]}{[HCOOH]}
Then, what is the definition of homogeneous and heterogeneous?
By what is an equilibrium affected?