Solve the equation:

2x-3 - 2x-1 = 1
x-3 2x+1


The 2x+1 is meant to be under the 2x-1

We won't do your homework for you, but I will give you a hint: multiply through by the prodiuct of the denominators:


\frac {2x-3} {x-3} - \frac {2x-1} {2x+ 1} = 1



\frac {(2x-3)(x-3)(2x+1)} {x-3} - \frac {(2x-1)(x-3)(2x+1)} {2x+ 1} = (2x-3)(2x-1)



(2x-3)(2x+1) -(2x-1)(x-3) = (2x-3)(2x-1)


Can you take it from here?