View Full Version : P(F≤3.48) for v_1=5,v_2=9
Verucasalt
Jun 6, 2010, 09:12 AM
what is the probability of this?
Verucasalt
Jun 6, 2010, 09:13 AM
P(F≤3.48) for v_1=5,v_2=9
Unknown008
Jun 6, 2010, 09:25 AM
More details would be welcomed.
What do F, v_1 and v_2 mean for instance?
EDIT: Ok, more distributions I am coming across... Thanks for the info galactus. (Lol, an 'eek' avatar)
galactus
Jun 6, 2010, 09:42 AM
This appears to be an F-distribution with degrees of freedom {\nu}_{1}=5 and {\nu}_{2}=9
That is not a v, but the Greek letter nu which resembles a v.
Looking in the F table for {\alpha}=.05, the value for 5 and 9 d.f. is indeed 3.48. I just looked.
I do not know what the poster is asking for, unless it is alpha (level of confidence)