paul ambrosino
Dec 9, 2006, 11:39 AM
A ball is thrown straight up at an initial speed of 50m per second. Neglect air resistance, how high does it go
Capuchin
Dec 9, 2006, 03:17 PM
look up your suvat equations.
You're looking for an equation that uses s, v, u, and a. (s is the height you're looking for)
plug in the numbers and you're done!
let me know if you need any more help
kesavan
Dec 28, 2006, 10:45 AM
^ using v^2=u^2+2as
0=50^2+2*(-10)*s
so s=125m we assume g=10ms-2