I need the answer

The trick here is to convert the cosecant function into its equivalent sin function, using:

csc(x) = 1/sin(x).

Can you take it from here?

If that is to be proved, then you use what ebaines suggested.

If you need to solve for x... well, you need to think about the proof ;)

Just one little "gotcha" to add - think about the range of csc(x), and avoid a situation of trying to determine a value for 0 \times \infty

Look at what sin(x)csc(x) is.

Since csc(x)=1/sin(x), then we have sin(x)/sin(x).

Of course, it equals 1 no matter the x value.

Of course, it equals 1 no matter the x value.

Actually, sin(x)csc(x) is undefined at x = 0.

Actually, sin(x)csc(x) is undefined at x = 0.

Yes, of course. I reckon I should have been more definitive.

sin(x)csc(x) = 1

For all values of x such that 0 is less than x is less than pi and pi is less than x is less than two times pi.

\{x|0<x<\pi, \pi<x<2\pi\}

I can't think of a better way to write it...

I can't think of a better way to write it...

How about:
For x \small {\ne} \large n\pi, where n = any integer.

Ah... I was wondering how you would say "x cannot be a factor of pi" but I wasn't sure. That works great.