Joe Fleet can jog at the rate of 8 mph. Ron Pack can hike carrying camping equipment at the rate of 4 mph. They leave from opposite ends of a 44-mile trail at the same time. How far does Ron travel if he has 15 minutes to set up camp before Joe arrives?

If I understood well, Ron should hike and put up the camp somewhere along the track, so that it is set up when Joe arrives. Ok.

Use the distance/speed/time formula for that.

Distance = Speed \times Time

Time = \frac{Distance}{Speed}

Time that Joe takes = \frac{x}{8}

Time that Ron takes = \frac{44-x}{4} + 0.25

Ron would travel the distance from the opposite end, hence why 44-x.
I added 0.25 hours from the time of Ron as Ron will take 0.25 hours (15 min) more time to set up the camp.

Now, their time should be equal since they meet.

So, equate both equations, to give

\frac{x}{8}= \frac{44-x}{4} + 0.25

Solve for x, the distance travelled by Joe.

Then, it'll be easy to find the distance Ron covers.

Post your answer! :)

(7rs^2)/(15t^2u)/(14s^3)/(5t^5u^4)