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seemamusic30
Apr 14, 2010, 12:52 PM
help me solve these problems:
1)A particle is exicuting SHM with time T .Starting from mean position ,what is the time taken by it to complete 5/8 oscillations ?
2)Two particles executing shm of same frequency meet at x= A/2 ,while moving in opposite directions . What is the phase difference between the particles?

InfoJunkie4Life
Apr 16, 2010, 07:37 PM
1. I think it is a duh question, SHM (Simple Harmonic Motion) refers to one complete sine wave movement. If it takes T to complete 1 full wave then it would take 5/8T to complete 5/8 of a complete wave. Probably one of those questions to show you know the meaning of the lingo here.

I could be wrong, its been a while for SHM

seemamusic30
Apr 17, 2010, 01:57 PM
No its not d answer!
D options given r :1)T/12
2)T/6
3)5T/12
4)7T/12