How can I calculate this? 4x^3=3.0x10^-16

I don't know how to figure out that when its like X^3
I can do X^2, but not on X^3
Please Help me Thanks

I need to find x of 4x^3=3.0x10^-16

I assume that what you mean is this:


4 x^3 = 3.0 \times 10^{-16}


First divide through by 4:


x^3 = 7.5 \times 10{-17}


Then take the cube root of both sides:


\sqrt[3] {x^3} = \sqrt[3] {7.5 \times 10 ^{-17}} \\
x = (7.5 \times 10 ^{-17})^{1/3} = (7.5 \times 10 \times 10 ^ {-18} ) ^{1/3} \\
= 75^{1/3} \times 10 ^ {-6}\\
= 4.217 \times 10^{-6}


Notice how by changing the exponent of 10 from 10^ {-17} to 10 \times 10^ {-18} it makes it easy to divide by 3 to get 10^{-6}