zetablue1
Mar 10, 2010, 08:44 PM
I have the following equation to solve:
We are going to try to apply the Standard Normal Distribution.
The average IQ for people is 100. The standard deviation is 16. Since I can't give you an IQ test we're going to make one up for each of you.
We'll do that as follows: take your age, divide by 2 and add 100. For this response use that value as your IQ, and determine what percentage of people would have a higher IQ. (e.g. Age = 40 y. Then you would determine percentage of people who have IQ greater than 120.)
This is what I came up with. Can you tell me if this is correct and if not where am I going wrong?
The IQ I am solving for is 44/2 + 100 = 122
122-100/16 = 22/16= 1.375
P(x>122) = P(z>1.375)
P(z>1.375 = 1-P(z<1.375)
= 1-0.9147 = 0.0853 = 8.5% people have an IQ of 122 or higher
We are going to try to apply the Standard Normal Distribution.
The average IQ for people is 100. The standard deviation is 16. Since I can't give you an IQ test we're going to make one up for each of you.
We'll do that as follows: take your age, divide by 2 and add 100. For this response use that value as your IQ, and determine what percentage of people would have a higher IQ. (e.g. Age = 40 y. Then you would determine percentage of people who have IQ greater than 120.)
This is what I came up with. Can you tell me if this is correct and if not where am I going wrong?
The IQ I am solving for is 44/2 + 100 = 122
122-100/16 = 22/16= 1.375
P(x>122) = P(z>1.375)
P(z>1.375 = 1-P(z<1.375)
= 1-0.9147 = 0.0853 = 8.5% people have an IQ of 122 or higher