View Full Version : How do you solve 3x 7y=-1 2x+3y=6 in the substitution method
DOAalex
Mar 4, 2010, 07:53 PM
I have tried the addition method on this problem where I multiple both equations if the constant but my teacher swears there is another better way so please help me
ROLCAM
Mar 4, 2010, 08:30 PM
3x + 7y= -1
2x + 3y= 6
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6X + 14Y = -2
-6X - 9Y = -18
________________
5Y = -20
Y = -4
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2x + 3y = 6
2X -12 = 6
2X = 6+12
2X = 18
X =9
_______________________
X=9
Y = -4
___________________________
proof:-
3x + 7y= -1 ****27-28 = -1
2x + 3y= 6 *****18-12 = 6
KISS
Mar 4, 2010, 09:32 PM
You need to solve one of the equations for x or y and substitute into the other one. It will be a little messy. Fractions.
Unknown008
Mar 5, 2010, 12:44 PM
Well, strictly speaking, yes, using substitution will give rise to fractions, making it a little messy.
You can try substituting something else instead of x or y to make is easier.
3x + 7y= -1
2x + 3y= 6
Multiply (I) by 2 and (ii) by 3.
6x + 14y= -2
6x + 9y= 24
Make 6x the subject of formula in the first equation.
6x = -2 - 14y
Now, substitute 6x by (-2 -14y) into the other equation, giving:
(-2 - 14y) + 9y= 24
You substituted 6x instead of x. Now it's easier.
KISS
Mar 5, 2010, 01:59 PM
Why didn't I think of that? (Can't spread rep).
Unknown008
Mar 6, 2010, 08:21 AM
Don't worry :) This happens to me as well.