Solid aluminum bromide and chloride gas react to produce bromine and solid aluminum chloride.

chemical equation?

AlBr + Cl = Br + AlCl

single replacement is what is used... sorry I don't have the proper numbers for the atoms but they should be on you perodic table with the +-

I have to disagree starfirefly. These are not the proper formulae.

Aluminium bromide - consist of aluminium and bromide ions, aluminium having a valency of 3 and bromide a valency of 1. This makes aluminium bromide have the formula AlBr_3

Chlorine gas has the formula: Cl_2

Aluminium chloride is written as AlCl_3

And bromine liquid is written as Br_2

The equation becomes:

AlBr_3 + Cl_2 \rightarrow AlCl_3 + Br_2

Now to balance, you need one more chlorine ion on the left, and one more bromine ion on the right. You need to put 3/2 in front of Cl2 and 3/2 in front of Br2. This way, you have 2* 3/2 = 3 chlorine atoms and 2 * 3/2 = 3 bromine atoms.

AlBr_3 + \frac32 Cl_2 \rightarrow AlCl_3 + \frac32 Br_2

The equation is now balanced. To remove the fractions, just multiply everything by 2.

2AlBr_3 + 3 Cl_2 \rightarrow 2AlCl_3 + 3 Br_2

You can count the atoms on the left and right. They are the same.