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View Full Version : Find the magnitude of the position vector (-'5,'11)


yesnimar
Feb 22, 2010, 07:40 PM
Find the magnitude of the position vector (-√5,√11)

Unknown008
Feb 23, 2010, 08:46 AM
The magnitude is given by:

\sqrt{x^2 + y^2}

just like the Pythagoras' theorem.

x is -\sqrt5 and y is \sqrt{11}