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Find the magnitude of the position vector (-'5,'11)
yesnimar
Feb 22, 2010, 07:40 PM
Find the magnitude of the position vector (-√5,√11)
Unknown008
Feb 23, 2010, 08:46 AM
The magnitude is given by:
\sqrt{x^2 + y^2}
just like the Pythagoras' theorem.
x is -\sqrt5 and y is \sqrt{11}