Could anybody help me out with this? I keep on trying this problem but end up with the wrong answer each time.

Mark is 10 years younger than Larry. Larry's age 8 years from now will exceed twice Mark's age 3 years ago by 4 years. How old is each now?

Mark is 10 yrs younger than Larry: M=L-10

"Larry's age 8 years from now will exceed twice Mark's age 3 years ago by 4 years. How old is each now?".


L+8=2(M-3)+4

L+8=2((L-10)-3)+4

Solve for L: L=30 and M=20

Therefore, Larry is 30 and Mark is 20.

Check the criteria:

Larry's age 8 yrs from now=38

Twice Mark's age 3 yrs ago=2(20-3)=34

Will exceed by 4 years: 38-34=4

There ya' go... QED.

m:x-10 l:x

after 8 years,

so x+8-2((x-10)-3)=4
x=30

m:20 l:30