For CO + NO2 ------yielding---CO2 + NO

Given that the activation energy is 135 kJ/mol of CO reacted, how can I find the heat of reaction?

225.794 KJ/mol is absorbed by this reaction...

If you take the heat of formation of the products combined and subtract the heat of formation of the reactants combined you get the heat of reaction.

I'm not sure if that helps... the number I got was calculated from the table at Wikipedia (http://en.wikipedia.org/wiki/Standard_enthalpy_change_of_formation_%28data_tabl e%29)