A skydiver falling toward the ground accelerates at 3.2m/s2. Calculate his displacement if after 8.0s he attained a velocity of 28m/s (down).

Use v = u + at to find the initial speed. Then, use v^2 = u^2 + 2as to find the displacement.

v is the final velocity
u is the initial velocity
a is acceleration
t is time
s is displacement