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rabbia
Sep 23, 2003, 06:58 PM
A stone is thrown from a bridge with a initial vertical velocity of magnitude 4.0m/s. Determine the stone's velocity after 2.2s if the direction of the initial velocity is
a) upward
b)down ward
Neglect air resistance
>?
How can I do this question

Bilal Yaqub Bandeesha
Jan 20, 2008, 10:06 PM
use vf=vi+gt for downward

jiten55
Jan 21, 2008, 03:21 AM
The formula is: v = u + at

Where: v = final velocity, u = initial velocity, a = acceleration

If thrown upward, acceleration = -g

If thrown downward, acceleration = g

justindq
May 16, 2008, 09:01 AM
use the formular v = u + at, where a is represented by g, being the force of gravity. A = -g if stone is thrown upwards and a = g when stone is thrown downwars. Hence for (a) formular is v = u - gt
and for (b) v = u + gt.

kesavan
May 16, 2008, 10:19 AM
These equations are vector equations. You can use any direction, but put components in the same directions

sajjadjeeven2
Aug 21, 2009, 03:53 AM
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