(4^2/4 * 4^-7/4) / (4^-10/4)

Just for clarification, do you mean this:


\frac { \frac {4^2} 4 \times \frac {4^{-7}} 4} {\frac {4 ^ {-10}} 4}


We're not going to just do your homework for you, so please try this problem yourself and show us how far you get or where you get stuck, and someone will help you from there.

this is more or less indices and logarithms
4^2/4 * 4^-7/4/4^-10/4
4^-5/4/4^-10/4
4^5/4
Ans= 4^5/4

The problem is we aren't even sure of what the OP means. I had some difficulty in understanding what you did, stellababe...

If the question was:

\frac{\frac{4^2}{4} \times 4^{\frac{-7}{4}}}{\frac{4^{-10}}{4}}

then the answer would be different :rolleyes:

It's just a suggestion.

All you need to know is, numbers with indices, and the base number is the same, i.e. 4^2 * 4^(-7/4), you add the indices. Also, the minus sign means putting the whole number over 1, and getting rid of the minus, so x^-2 = 1/(x^2). This is all that is needed for this, and u can then work it out. I don't see a need for logs if your only evaluating this.