I need to prove the following

sinxcot(x/2)=cosx+1

I'm usually OK in math but have a huge trig block... help!

Please put parenthesis where needed. Is that cos(x) or cos (x+1), is that sin(x)cot(x/2) or sin(cot(x/2))?

Well, what I would have done is:

1. Convert all into half angle, in terms of cos and sin only:

sinxcot(\frac{x}{2}) = 2sin (\frac{x}{2}) cos (\frac{x}{2}) \frac{cos(\frac{x}{2})}{sin(\frac{x}{2})}

Then, cross out the ones which cancel:

2\cancel{sin (\frac{x}{2})} cos (\frac{x}{2}) \frac{cos(\frac{x}{2})}{\cancel{sin(\frac{x}{2})}} = 2cos^2(\frac{x}{2})

Then, transform back to single angle using the identity:

cos2A = 2cos^2 A -1

This should lead you to the answer.

I hope it helped! :)

how to solve 1+cot^2x/cscx=1/sinx

What is 1+cot^2x? That is the equivalent of cosec^2x
You have cosec^2x and cosecx which reduce to cosecx. What is the definition of cosec? That will give you the answer.