A triangle has sides of length 5,6 and 7 units. Find the largest angle to the nearest minute


Thanks in advance

Draw a diagram of the triangle, a sketch will do, with each side larger than the previous.

Look for the largest angle. You'll see that it lies between the sides of 5 and 6 units.

Then, use the cosine rule to fond the size of the angle.

a^2 = b^2 + c^2 - 2bccos(A)

Post what you did.

You'll also have to convert the digits after the decimal point into minutes (60 minutes in a degree)