View Full Version : Rearranging a formula 2
leonardo1841
Nov 14, 2009, 10:38 AM
There is also another formula which is confusing
Make e the subject
T = (1 + e/1 – e) x √L/10
Unknown008
Nov 14, 2009, 09:58 PM
T = \frac{1+e}{1-e}\ \times \ \frac{\sqrt{L}}{10}
Is that it?
leonardo1841
Nov 15, 2009, 04:03 AM
Sorry, I mistyped it there is meant to be a 5 instead of a 10, and the square root is over the whole of L/5
Unknown008
Nov 15, 2009, 06:05 AM
Ok, so;
T = \frac{1+e}{1-e} \times \sqrt{\frac{L}{5}}
Multiply by 1-e, on both sides:
T(1-e) = \frac{1+e}{\cancel{1-e}} \times \sqrt{\frac{L}{5}} \times \cancel{(1-e)}
Expand both sides:
T-eT = \sqrt{\frac{L}{5}} +e\sqrt{\frac{L}{5}}
Bring all the 'e' on one side:
T\cancel{-eT + eT} - \sqrt{\frac{L}{5}} = \cancel{\sqrt{\frac{L}{5}}} +e\sqrt{\frac{L}{5}}+ eT\cancel{ - \sqrt{\frac{L}{5}}}
T- \sqrt{\frac{L}{5}} = e\sqrt{\frac{L}{5}}+ eT
Then factorise e;
T - \sqrt{\frac{L}{5}} =e(\sqrt{\frac{L}{5}}+ T)
It's nearly finished, can you take it now? :)
I hope it helped! :)