starfirefly
Oct 29, 2009, 07:50 PM
I'm really stuck on this question... my math examples skip steps and I don't understand it this is what it says.. all I need to know is what steps are missing any help would be appreciated.
2x-5y=4
-5y=-2x+4 after this I'm so lost
y=2/5x-4/5
slope is 2/5
KISS
Oct 29, 2009, 08:44 PM
Seems simple enough:
2x-5y=4
Actually, you just want the form y = mx+b, then m is the slope and b is the y intercept (x=0)
You want a positive y, so you nned to re-arrange the eqn as:
2x=5y+4 ; all I did here was make y positive
re-arranging as close to y = mx +b
2x-4 = 5y
re-arrange again
a) 5y=2x-4
almost. Now get y by itself by dividing by 5
y = 2/5(x) - 4/5
slope is 2/5
or, from where you got lost
-5y=-2x+4
multiply both sides by -1;
and your at my eqn labeled a
5y = 2x -4