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Kaykay09
Oct 19, 2009, 06:14 PM
If there were 5 red octopuses in the ocean, 7 purple octopuses and 9 orange octopuses, what is the probability that you'd see 3 orange octopuses? :confused: help!! I need to know this answer tonight please!

Nhatkiem
Oct 19, 2009, 06:16 PM
If there were 5 red octopuses in the ocean, 7 purple octopuses and 9 orange octopuses, what is the probability that you'd see 3 orange octopuses??:confused: help!!! i need to know this answer tonight please!!

Do you mean what are the odds of spotting 3 orange ones in a row, out of 3 tries?

Kaykay09
Oct 19, 2009, 06:19 PM
No.. altogether in my question there are 21 total octopuses. And there are 9 orange ones. What's the chance we're going to see 3 of those orange ones?

Kaykay09
Oct 19, 2009, 06:20 PM
Would it be 9 out of 21?

Nhatkiem
Oct 19, 2009, 06:21 PM
No..altogether in my question there are 21 total octopuses. and there are 9 orange ones. whats the chance we're gunna see 3 of those orange ones?

I understand that :o, however I am asking what is the number of octopi you can see. You may want to find 3 orange ones, but is 3 the maximum amount, or perhaps is it 5? Or 6 octopi?

Kaykay09
Oct 19, 2009, 06:22 PM
I understand that :o, however I am asking what is the number of octopi you can see. you may want to find 3 orange ones, but is 3 the maximum amount, or perhaps is it 5? or 6 octopi?

The max number is 21

Nhatkiem
Oct 19, 2009, 06:23 PM
Hahah, no no, I think you are misunderstanding me. For example, I have 10 red marbles, 6 blue marbles. I want at least 2 blue marbles, but I can pick up to 4.

I'm asking how many your allowed to pick, not just what you want to pick.

Kaykay09
Oct 19, 2009, 06:25 PM
you're allowed to pick 9 because there's 9 orange ones haha I think I'm sorry if I'm confusing I'm new at all this probability stuff :p

Nhatkiem
Oct 19, 2009, 06:28 PM
Ahh well if your new then its probably not what I'm thinking of.

If your looking for just the probability of spotting 3 orange octopi in a row, it would be the probability of the spotting the first one times the probability of spotting the second one... etc.

so you're probability would be
let O represent the number of orange octopi, and N represent total octopi

probability = \frac{O}{N}*\frac{O-1}{N-1}*\frac{O-2}{N-2}

Nhatkiem
Oct 19, 2009, 06:29 PM
Sorry that "a" should be a "1" in the (N-a), must have miss punched a key..

Kaykay09
Oct 19, 2009, 06:30 PM
Yeah haha. Oh okay... yeah! Okay! Thank you for your help!

Kaykay09
Oct 19, 2009, 06:31 PM
Yeah haha. Oooo ohh okay.. yeah! Well thank you very very much for your help!

Unknown008
Oct 20, 2009, 04:20 AM
I think the question was seeing the octopi altogether, which brings it to 9/21 * 8/20 * 7/19. I don't have a calculator with me :o

Kaykay09
Oct 21, 2009, 07:19 AM
Thanks jerry! That made a lot of sense! And that's true haha

Nhatkiem
Oct 21, 2009, 11:19 AM
I think the question was seeing the octopi altogether, which brings it to 9/21 * 8/20 * 7/19. I don't have a calculator with me :o

That's equivalent to my \frac{O}{N}*\frac{O-1}{N-1}*\frac{O-2}{N-2}:p

Unknown008
Oct 21, 2009, 11:28 AM
Oh sorry, I thought you were posting another binomial expansion again :o

Nhatkiem
Oct 21, 2009, 11:35 AM
Oh sorry, I thought you were posting another binomial expansion again :o

HAHAHA, I'd figured after a page of asking her that it probably wasn't binomial expansion :D

Chris-infj
Oct 23, 2009, 08:02 AM
Which is equivalent to (9C3) over (21C3) on a calculator.

Nhatkiem
Oct 23, 2009, 09:26 AM
Yeah but calculators are no fun :p

Chris-infj
Oct 23, 2009, 10:02 AM
LOL, you are right, garbage in, garbage out