Hey could I have some help with these:

(b) 6 3 0 2
x − x + = by completing the square (giving an exact answer simplified if
possible). (3 marks)


(c) 2 7 3 2
x − x = by the formula (giving exact answers).

Hey could i have some help with these:

(b) 6 3 0 2
x − x + = by completing the square (giving an exact answer simplified if
possible). (3 marks)


(c) 2 7 3 2
x − x = by the formula (giving exact answers).

(b) x^2 - 6x + 3 = 0 by completing the square (giving an exact answer simplified if
possible). (3 marks)
(c) 2x^2 - 7x = 3 by the formula (giving exact answers). (2 marks)

sorry there are the questions

For an equation ax^2 + bx + c = 0, the completed square form is:

a(x+\frac{b}{2a})^2 - \frac{b^2}{4a} + c

To do that, first of all remove (by factorisation) the coefficient of x^2:

ax^2 + bx + c = 0

a(x^2 + \frac{bx}{a}) + c = 0

Then, divide the coefficient of x by 2, replace x^2 by x and x by 1. Put all into brackets and square them. Also, subtract the square of the coefficient of x you just divided by 2:

a[(x + \frac{b}{2a})^2 - (\frac{b}{2a})^2] + c = 0

Then, re expand your values:

a(x + \frac{b}{2a})^2 - (a)(\frac{b^2}{4a^2}) + c = 0

a(x + \frac{b}{2a})^2 - \frac{b^2}{4a} + c = 0

Care to try the part (b) that you asked?

I (or another member) will tell you whether this is good.