antifrog16
Oct 13, 2009, 01:31 PM
Hey could I have some help with these:
(b) 6 3 0 2
x − x + = by completing the square (giving an exact answer simplified if
possible). (3 marks)
(c) 2 7 3 2
x − x = by the formula (giving exact answers).
antifrog16
Oct 13, 2009, 01:35 PM
Hey could i have some help with these:
(b) 6 3 0 2
x − x + = by completing the square (giving an exact answer simplified if
possible). (3 marks)
(c) 2 7 3 2
x − x = by the formula (giving exact answers).
(b) x^2 - 6x + 3 = 0 by completing the square (giving an exact answer simplified if
possible). (3 marks)
(c) 2x^2 - 7x = 3 by the formula (giving exact answers). (2 marks)
sorry there are the questions
Unknown008
Oct 14, 2009, 10:50 AM
For an equation ax^2 + bx + c = 0, the completed square form is:
a(x+\frac{b}{2a})^2 - \frac{b^2}{4a} + c
To do that, first of all remove (by factorisation) the coefficient of x^2:
ax^2 + bx + c = 0
a(x^2 + \frac{bx}{a}) + c = 0
Then, divide the coefficient of x by 2, replace x^2 by x and x by 1. Put all into brackets and square them. Also, subtract the square of the coefficient of x you just divided by 2:
a[(x + \frac{b}{2a})^2 - (\frac{b}{2a})^2] + c = 0
Then, re expand your values:
a(x + \frac{b}{2a})^2 - (a)(\frac{b^2}{4a^2}) + c = 0
a(x + \frac{b}{2a})^2 - \frac{b^2}{4a} + c = 0
Care to try the part (b) that you asked?
I (or another member) will tell you whether this is good.