baby_me
Oct 13, 2009, 04:33 AM
At 298 K, Kc for N2O (g) <---- 2NO (g) is 5. 98 x 10 -3. How many moles of NO2 are in equilibrium with 0.25 mole N2O4 in a 475 mL flask?
I need the answer.I don't know what to do.:confused:
Perito
Oct 13, 2009, 02:49 PM
At 298 K, Kc for N2O (g) <---- 2NO (g) is 5. 98 x 10 -3. How many moles of NO2 are in equilibrium with 0.25 mole N2O4 in a 475 mL flask?
i need the answer.I don't know what to do.:confused:
First, you need a balanced equation:
Second, using that equation, you write down the definition of Kc
Are you sure your reaction is correct?
2NO \rightarrow N_2O\,\,\,??
You have to reduce the NO to nitrous oxide, N2O. While that's definitely feasible, I'd be afraid it would decompose to nitrogen and oxygen first.
2NO \rightarrow N_2O + \frac 12 O_2