ritia
Oct 7, 2009, 08:38 PM
how do you solve the equation in the given interval?
sin x= 0.6, 0<or equal to x<or equal to 2pi
Unknown008
Oct 8, 2009, 01:58 AM
Grab your calculator and type sin{-1}(0.6). You should have 0.644 radians.
Now, sine is positive in the first and second quadrant. So, your solutions will be:
x = 0.644^c \,, \pi - 0.644
x = 0.644^c \,, 2.50^c
I hope it helped! :)
PS. And please, do not type in with CAPS on, this is equivalent to shouting.