Solve for x in the below algebraic equation

3^2x + 19 = 10^x

Sorry :o I'll give it a try later on... I did a very big mistake

EDIT: Ok, now I'll do it.

The only way that I see, is that you have to solve this by graphing, or iterations, if you know how to do it.

Draw the graph of y=3^{2x}+19 and y=10^x.

Look for the point of intersection, and check it's x coordinate, which is the solution to your answer.

I was trying the iteration, and was looking for the point where the sign changes, and found that x = 2 solved the equation...