View Full Version : Traffic jam! Help! Number problems and Equations!
Kyo_of_Dir_en_grey
Nov 1, 2006, 05:24 PM
Ok I will be posting a lot of questions in this thread for the sake of trying not to clutter up the forums... so if you get the stuff I am talking about please stick around and help me out... I would love you forever... :p
Ok so right at the moment I am having trouble with this problem here I am normaly OK at setting them up but I can figure this one out :eek:
A larger number minus a smaller number is 18. The larger number is three times the smaller. Find the numbers.
I am also having trouble as to how to do these kinds of problems all together XD...
3/4q-7=8
and like...
c-5/4=3
and las but never least
h/3-4=13
I am failing math guys ANY help would be luffed!:o
jham_lindow
Nov 1, 2006, 06:42 PM
Ok I will be posting alot of questions in this thread for the sake of trying not to clutter up the forums....so if you get the stuff I am talking about please stick around and help me out...I would love you forever...:p
Ok so right at the moment I am having trouble with this problem here I am normaly ok at setting them up but I can figure this one out :eek:
I am also having trouble as to how to do these kinds of problems all together XD...
3/4q-7=8
and like...
and las but never least
I am failing math guys ANY help would be luffed!:o
Lets start with the number problems.
3/4q-7=8
just add 7 to each side
3/4q=15
mulitply by 3/4
and q=11.2
c-5/4=3
add 5/4 to 3
c=4 1/4
h/3-4=13
multiply by 3-4
h=3(3-4)
distribute the 3
h=9-12
then subtract
h=-3
now the word problem
A larger number minus a smaller number is 18. The larger number is three times the smaller. Find the numbers.
set it up
x-y=18 and x=3y
3y-y=18
subtract
2y=18
divide
y=9
x-9=18
add 9 to each side
x=27
small number 9, large number 27
s_cianci
Nov 1, 2006, 08:49 PM
Ok I will be posting alot of questions in this thread for the sake of trying not to clutter up the forums....so if you get the stuff I am talking about please stick around and help me out...I would love you forever...:p
Ok so right at the moment I am having trouble with this problem here I am normaly ok at setting them up but I can figure this one out :eek:
A larger number minus a smaller number is 18. The larger number is three times the smaller. Find the numbers.
I am also having trouble as to how to do these kinds of problems all together XD...
3/4q-7=8
and like...
c-5/4=3
and las but never least
h/3-4=13
I am failing math guys ANY help would be luffed!:o
1. Let the numbers be represented by 3x and x. Then, 3x - x = 18 ; 2x = 18 ; x = 9 and 3x = 27 so your numbres are 27 and 9.
2. Do you mean (3/4)q - 7 = 8 or 3/(4q) - 7 = 8? Is the q in the numerator or the denominator? It's hard to tell from the way you typed the question and that'll make a big difference.
3. Same uncertainty here ; did you mean c - (5/4) = 3 or (c - 5)/4 = 3?
4. h/3 - 4 = 13
h/3 = 17
h = 51