Listed below are solubility vs temperature data for an organic compound in water.

temp. sol. In 10 mL water
0 0.15 g
20 0.30 g
40 0.65 g
60 1.10 g
80 1.70 g

a) Using the data in the above table, graph the solubility of the compound vs temperature. Connect the data points with a smooth curve.


b) Suppose 0.1 g of this compound is mixed with 1.0 mL of water and heated to 80° C. Would all of the compound dissolve? Explain.


Could anybody help me in this Q ?

I solved a but b I didn't understand it. .

Sure:

A:) X is temp by the 20's and Y is the grams of compound by, say, 5's. Put down some dots and draw a line

B:) If 10mL dissolves 1.7g at 80 degrees, then you can cross multiply:

\frac{1.7}{10} = \frac{x}{1}

doing this would tell you that 0.17g can be dissolved in 1mL of water. Thus it is possible to dissolve 0.1g in it.

Thanks,

I have to explain why the compound will dissolve. .

So how can I know that 0.17g can be dissolved in 1mL of water ? I mean how you know it will dissolve ?

It is said that 1.7g dissolves in 10 mL of water at 80 C, from your table.

Using proportion, 1.7 g -> 10 mL
10 mL -> 1.7 g
1 mL -> 0.17 g

0.17g is the maximum mass that will dissolve. So, if you have 0.1 g (which is less that 0.17g), all will dissolve at 80 C.

Does that help? :)

Yaaa it help. .

Thanks. .

You're welcome! :)