cxbryant
Sep 29, 2009, 09:45 AM
A 500.0-g iron bar at 212 degrees Celsius is placed in 2.0-L if water at 24.0 degrees Celsius. What will be the change in temperature of the water? Assume no heat is lost to the surroundings.
Unknown008
Sep 29, 2009, 10:01 AM
Use your formula Q = mc\Delta T
Since the no heat is lost, the magnitude (value) of both 'Q's are the same:
Q_{water} = Q_{iron}
m_{water}c_{water}\Delta T = m_{iron}c_{iron}\Delta T
(2\, kg)c_{water}(T_f - 24) = (0.5\, kg)c_{iron}(T_f-212)
You must have the specific heat capacity of water and iron. Replace c by their corresponding values and solve for Tf, the final temperature.
I hope it helped!:)