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nappan01
Sep 23, 2009, 02:29 AM
Suppose a bear travels 2 km/hr due east for 30 minutes, 4km/ hr northeast for 15 minutes then 6 km/hr due west for 15 minutes.
a) what distance did the bear travel during this trip?
b) what was the bear's average speed during the trip?
c) at the end of the trip, what displacement (magnitude and direction) did the bear have relative to its starting position?
d) what was the bear's average velocity (magnitude and direction) during the trip?

Cedarln2265
Sep 23, 2009, 07:52 AM
Is this for your homework?

Unknown008
Sep 23, 2009, 12:12 PM
1. Use Distance = Speed \times Time

2. Average\, Speed = \frac{Total\, Distance}{Total\, Time}

3. Have a sketch and use your trigonometry to find the distance from the starting point to the end point (that's displacement)

4. Average\, velocity = \frac{Displacement}{Total\, time}