A car with an intitial speed of 23.2 km/h accaelerates at a uniform rate of 0.92 m/s^2 for 3.8 s.
Find the final speed of car. Wat is the displacement of the car after that time> answer in km

You'll need a combination of two formulas. The first is distance is equal to (initial velocity in m/s times time in seconds) plus (1/2 times acceleration in m/s squared times time squared in seconds). Once you find this distance, which is the same thing as displacement in this case, use a seconf formula, which is final velocity in m/s is equal to (2 times distance in meters divided by time in seconds) minus the initial velocity in m/s. There are lots of other formulas you could use for the second part because of all the variables you were supplied with and all of the ones you can find. I suggest making a formula list of all the formulas you learn in class and in your textbook and include the units and any notes about when you might use the formulas. This really helped me. Hope this helps!
(Sorry about the wordy formulas, I don`t know how to write that kind of stuff on a computer)

Ok, I'll put in into symbols for marzipan6.

1st formula: s = ut + \frac12 at^2

2nd formula: v = \frac{2s}{t} - u

However, I prefer doing it like this:

1. To find final speed, use v = u+ at

2. To find displacement, use s = ut + \frac12 at^2

In all of these formulae,
u = initial velocity
v = final velocity
s = displacement
t = time
a = acceleration.

Hope it helped! :)