What are the probabilities of getting an a's in a deck of standar cards?

It's not that hard if you think about it, it's a fraction. 4/52 right? 4 Aces, 52 cards in a pack.

Ino and the answer is 1/13 right? But in my math but at the ack of the book it says that the answer is 10/13 and not one? How come? Because I no that if I put 40 divide it by 52 its 10/13 so that's why I don't get it

Well crap, that's weird. I wish my boyfriend was here, cause he'd know off the top of his head.

Well crap, that's weird. I wish my boyfriend was here, cause he'd know off the top of his head.


Or maybe the book is wrong!

Your book was definitely wrong.

what are the probabilities of getting an a's in a deck of standar cards?

Merliot - please write the question out exactly as it appears in your book. Based on the discussion in this thread there seems to be confusion over the wording of the problem.

Based on what you ask the chances are 1 in 13. If the books says something else the question is faulty or the answer is wrong. Just because something is in print doesn't isure it correct. I visited the Chicago museum of Science and Industry yesterday and saw many examples of errors printed in their displays.

I don't know, the answer is effectively 1, but there are probably some freak manufacturing faults where no aces are included in the deck. I would suspect an answer much higher than 10/13 though.

I think too it's an error in the book. The 1/13 is very similar to 10/13, in the way that only the zero is present. Such can very easily arise when the book was written.