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dportal2006
Sep 11, 2009, 05:34 PM
http://i927.photobucket.com/albums/ad115/dportal2006/scan0001.jpg

This link has the exact graph that relates to my question.

I have tried answering the question however, the formula that is provided in my book for instantaneous velocity is change of V/change of t as the limit of t approaches 0. The problem is that when they are asking me the instantaneous speed of the first point like A , what is the second point that I need to use to input the change of velocity and t on the formula?

I really appreciate the help. Thank you.

Unknown008
Sep 11, 2009, 09:11 PM
You have to understand that \frac{dv}{dt} is the gradient of the graph. If I ask you what is the gradient of the graph at the point A. Can you find the instantaneous velocity?

I hope it helped! :)