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peri42
Aug 22, 2009, 04:26 PM
Factor 1) x^4-16y^4


2)y^6-8x^3

galactus
Aug 22, 2009, 05:25 PM
Factor 1) x^4-16y^4

Difference of two squares. (x^{2})^{2}-(4y^{2})^{2}

I assume you already know that the difference of two squares factorization is

x^{2}-y^{2}=(x+y)(x-y)


2)y^6-8x^3

Difference of two cubes:

x^{3}-y^{3}=(x-y)(x^{2}+xy+y^{2})

(y^{2})^{3}-(2x)^{3}

peri42
Aug 23, 2009, 01:18 PM
alrite thanks 4 your help! =)