Factor 1) x^4-16y^4


2)y^6-8x^3

Factor 1) x^4-16y^4

Difference of two squares. (x^{2})^{2}-(4y^{2})^{2}

I assume you already know that the difference of two squares factorization is

x^{2}-y^{2}=(x+y)(x-y)


2)y^6-8x^3

Difference of two cubes:

x^{3}-y^{3}=(x-y)(x^{2}+xy+y^{2})

(y^{2})^{3}-(2x)^{3}

alrite thanks 4 your help! =)