A GREE FROG WITH A BODY TEMPERATURE OF 18 Celsius AT REST AT THE EDGE OF A 1.0m HIGH TABLE JUMPS OFF AND LANDS ON THE GROUND 1.0 m out from the edge.determine the length of its displacement vector.

Please refrain from using ALL CAPITALS in the future. Thank you.
I assume you mean a green frog.

Anyway, to find the answer is very simple. Simply use the pythagorean theorum to get it.

He goes 1m down, and 1m across...

EDIT: Listen to Unknown, I don't know what I was thinking... :o

I have to disagree with something you said just then HH...

The Pythagoras' Theorem does work with ones:

\sqrt{1^2+1^2} = \sqrt{1+1} = \sqrt2

I have to disagree with something you said just then HH...

The Pythagoras' Theorem does work with ones:

\sqrt{1^2+1^2} = \sqrt{1+1} = \sqrt2

Hey, yeah, you're right, I don't know what I was thinking. I edited my previous post to limit confusion. Thanks Unknown!

It's OK, we all have some time when we don't know what were doing ;)

The velocity as a function of time for an asteroid in the asteroid belt is given by
v(t)=V0e^(-t/t0) I + v0t/2t0 j

with vo and to constants.

Use ti = 0 as the initial time, and tf = 1.5 to as the final time.

The values for the constants that you will use are:

vo = 4.5 m/s
to = 80 s

Find the displacement of the asteroid.
delta R= I+ j

sbiyouka: I see you asked the same question here: https://www.askmehelpdesk.com/physics/physics-765240.html

Please see my repsone there.