A car is traveling at a constant velocity. After two hours the car has traveled 110 miles. After four hours the car has traveled 220 miles. Assuming a linear equation fits this situation, find the linear equation for the given data.

You have all the required data, you can do it easily.

You have two points, well they are disguised.

I'll say let distance be y, and time be x.

x_1 = 2 and y_1 = 110

Those are the first pieces of information you are given, and you may represent them as (2, 110)

Then,

x_2 = 4 and y_2 = 220

Again, you have (4, 220)

You have two points, use the formula \frac{y_2-y_1}{x_2-x_1} = m to find the gradient m.

Then to have the equation, use:\frac{y-(y-coordinate)}{x-(x-coordinate)} = m

Hope it helped! :)