A chemist wants to prepare 200mL of a saturated solution of BaF2, the ocncentration of which is 6.3 X 10-3mol/L. what mass of BaF2 will be needed to make up the 200mL. Of the solution.

I said .2L X 6.3 X 10-3 ml./L = 1.26 X 10-3mol



Using the molar mass of BaF2 = 175g/mol,

175 g/mol X 1.26 X 10-3 mol

= .220g

Is this right?

A chemist wants to prepare 200mL of a saturated solution of BaF2, the concentration of which is 6.3 X 10-3mol/L. what mass of BaF2 will be needed to make up the 200mL. Of the solution.

I said .2L X 6.3 X 10-3 ml./L = 1.26 X 10-3mol

Using the molar mass of BaF2 = 175g/mol,

175 g/mol X 1.26 X 10-3 mol

= .220g



Yes, you are correct. Your logic is flawless. Congratulations!