I need help with solving this problem: Find the value of E, the margin of error, for c=0.90, n=10 and s= 3.7
Thanks!

E=z\cdot \frac{s}{\sqrt{n}}

Find the z score that corresponds to .90 confidence interval and plug and chug.

I have rainfall data of some stations. I have also normals of rainfall for these stations. I want to perform Trend Analysis, Statistical significance, Kurtosis etc. on this data. I am giving example of data of a sation.

Station Year June (mm) normal(mm)
Delhi 1960 40 50
61 30
62 60
63 40
64 28
65 60
66 58
67 48
68 58
69 61
70 63
71 68
72 45
73 52
74 55
75 58
76 60
77 48
78 51
79 53
80 49
81 53
82 54
83 55
84 61
85 63
86 49
87 52
88 49
89 52
90 51
91 53
92 54
93 49
94 51
95 53
96 56
97 45
98 48
99 52
2000 46

VIZAYA BHASKAR;1895329]

I have rainfall data of some

stations. I have also normals of rainfall for these stations. I want to perform Trend

Analysis, Statistical significance, Kurtosis etc. on this data. I am giving example of data of

a sation.

[B

Station Year June (mm) normal(mm)
Delhi 1960 40 50
61 30
62 60
63 40
64 28
65 60
66 58
67 48
68 58
69 61
70 63
71 68
72 45
73 52
74 55
75 58
76 60
77 48
78 51
79 53
80 49
81 53
82 54
83 55
84 61
85 63
86 49
87 52
88 49
89 52
90 51
91 53
92 54
93 49
94 51
95 53
96 56
97 45
98 48
99 52
2000 46

VIZAYA BHASKAR;1895329] I have rainfall data of some stations. I have also normals of

Rainfall for these stations. I want to perform Trend Analysis, Statistical significance,

Kurtosis etc. on this data. I am giving example of data of a sation.

Station Year June (mm) normal(mm)
Delhi 1960 40 50
61 30
62 60
63 40
64 28
65 60
66 58
67 48
68 58
69 61
70 63
71 68
72 45
73 52
74 55
75 58
76 60
77 48
78 51
79 53
80 49
81 53
82 54
83 55
84 61
85 63
86 49
87 52
88 49
89 52
90 51
91 53
92 54
93 49
94 51
95 53
96 56
97 45
98 48
99 52
2000 46[/QUOTE]

E=z\cdot \frac{s}{\sqrt{n}}

Find the z score that corresponds to .90 confidence interval and plug and chug.

How about a t score. :-)

Vizaya, it would be nice if you would start your own thread for your own problem. It would also be nice if you didn't post it three times - that is unnecessary.