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View Full Version : Complex no.s in cartesian form


Vi Nguyen
Jul 3, 2009, 04:35 AM
Express in cartesian form a+ib, with a,b as real numbers:

1/(1+cosβ+isinβ)

Thanks ;p

galactus
Jul 3, 2009, 08:01 AM
I assume you mean like this:

\frac{1}{2}-\frac{tan(\frac{\beta}{2})i}{2}

Vi Nguyen
Jul 5, 2009, 04:52 AM
No, apparently the answer is .5(1-i(sinbeta/1+cosbeta).


I assume you mean like this:

\frac{1}{2}-\frac{tan(\frac{\beta}{2})i}{2}

galactus
Jul 5, 2009, 05:57 AM
That's the same thing. Know your trig identities?

tan(\frac{x}{2})=\frac{sin(x)}{1+cos(x)}=\frac{1-cos(x)}{sin(x)}