Express in cartesian form a+ib, with a,b as real numbers:

1/(1+cosβ+isinβ)

Thanks ;p

I assume you mean like this:

\frac{1}{2}-\frac{tan(\frac{\beta}{2})i}{2}

No, apparently the answer is .5(1-i(sinbeta/1+cosbeta).


I assume you mean like this:

\frac{1}{2}-\frac{tan(\frac{\beta}{2})i}{2}

That's the same thing. Know your trig identities?

tan(\frac{x}{2})=\frac{sin(x)}{1+cos(x)}=\frac{1-cos(x)}{sin(x)}