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Aimee-Dame
Jun 25, 2009, 04:56 PM
In rolling 2 six sided die how do I figure out what the probability is of:
a) rolling an even #
b) rolling a #3
c) rolling a # 2 or 3?
Thanks!

Perito
Jun 25, 2009, 06:55 PM
This is the brute force way.

In two six-sided dice, you can throw numbers from 2 through 12. Each die is independent of the other so what you throw on one die does not affect what will come up on the second die. Right?

There is 1 way to produce a 2 - (1&1)
There are 2 ways to produce a 3 (1&2 and 2&1)
There are 3 ways to produce a 4 (1&3, 2&2, 3&1)
There are 4 ways to produce a 5 (1&4, 2&3, 3&2, 4&1)

...
There is 1 way to produce a 12 - (6&6)

Gee, a pattern seems to be emerging. Continue with this until you figure out all possibilities. Sum the "ways to produce". This sum will always be in the denominator. This is the total number of possibilities.

Add up the ways you can form even numbers and put that in the numerator. You now have your answer for 1).

Repeat for the others.