Given the equation of a circle (x+5)^2 + (y-3)^2 = 49 find the center and radius. How would I calculate this problem?

Given the equation of a circle (x+5)^2 + (y-3)^2 = 49 find the center and radius. How would I calculate this problem?


The equation for a circle is

(x-a)^2 + (y-b)^2 = r^2

where a and b are the x and y coordinates of the center (a,b).

In your case

(x+5)^2 + (y-3)^2 = 49

by inspection, the center is at (-5, 3). The radius is sqrt{49} = 7