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spg25
Jun 9, 2009, 10:44 AM
How to convert enthalpy of fusion (delta H) with units in kJ/mol to J/mm3?


I have a paper which says that enthalpy of fusion of copper (13.01 kJ/mol) is 5.9 J/mm3. I could not figure out how to arrive at the answer. Please help..

Perito
Jun 9, 2009, 11:23 AM
You need to convert mm^3 to moles or vice-versa. The density of copper is 8.94\,\frac {g}{cm^3}. The atomic weight of copper is 65.546\,\frac {g}{mole}

\frac {8.94\,g}{cm^3} \times \frac {1\,mole }{65.546\,g} \times \frac {1\,cm^3}{1000\,mm^3} \approx 1.364\times 10^{-4} \,\frac {mole}{mm^3}

Can you figure it out from there?

spg25
Jun 9, 2009, 11:30 AM
You need to convert mm^3 to moles or vice-versa. The density of copper is 8.94\,\frac {g}{cm^3}. The atomic weight of copper is 65.546\,\frac {g}{mole}

\frac {8.94\,g}{cm^3} \times \frac {1\,mole }{65.546\,g} \times \frac {1\,cm^3}{1000\,mm^3} \approx 1.364\times 10^{-4} \,\frac {mole}{mm^3}

Can you figure it out from there?



Thank you very much!!

bms251271
Jun 11, 2009, 11:30 PM
How to convert enthalpy of fusion (delta H) with units in kJ/mol to J/mm3?


I have a paper which says that enthalpy of fusion of copper (13.01 kJ/mol) is 5.9 J/mm3. I could not figure out how to arrive at the answer. Please help..

work on the relation pV=nRuT where V is the vol in cubic mm and you will able to get the same result in J/mm3