((1+tan(x))/(sin(x)))-sec(x)=csc(x)

((1+tan(x))/(sin(x)))-sec(x)=csc(x)

((1+tan(x))/(sin(x)))-sec(x)=csc(x)

\frac {(1+tan(x))}{sin(x)}-sec(x) = csc(x)

\frac {(1+\frac {sin(x)}{cos(x)})}{sin(x)}-\frac {1}{cos(x)} = \frac {1}{sin(x)}

\frac {\frac {(cos(x)+sin(x)}{cos(x)})}{sin(x)}-\frac {1}{cos(x)} = \frac {1}{sin(x)}

\frac {cos(x)+sin(x)}{sin(x)\,cos(x)}-\frac {sin(x)}{xin(x)\,cos(x)} = \frac {1}{sin(x)}

\frac {cos(x)}{sin(x)\,cos(x)} = \frac {1}{sin(x)}

\frac {1}{sin(x)} = \frac {1}{sin(x)} QED

The earth revolves on its axis once every 24 hours.Assumming the earth's radius is 6400 km, find the:

a.angular velocity of the earth in radians/day

b.angular velocity of the earth in
Radians/hour

c.linear velocity of a city located on the equator in km/hour

teshii18, you should have started your own thread.

a. Angular Velocity = Total angle covered/Time to cover angle

b. Just convert 1 radian/day = 1 radian/24 hours = 0.04166 rad/hour

c. Linear Velocity = Length of arc/Time to cover that length.