1.Complete the nuclear equation

7Li + 1H-->2 4He Is this correct?
3 1 2


4.One reaction that interest nuclear fusion researchers involves the fusion of deuterium and tritium to form alpha particles.
a. Write the nuclear equation for this reaction.

b.name any other particle the reaction produces.

can someone explain this for me please and show me how to do it? :confused: :confused:

7.Suggest a sequence you could use to change the mercury isotope, mercury-200, into gold-196. Write nuclear equations for the reaction.

really appreciate the help. :D

For the first question, the ( 1 ) belongs under the H and ( 2 ) is under the number 4

Your first question is correct.

Your second question involves deuterium and tritium,

^2_1D + ^3_1T {\rightarrow} {^4_2} \alpha + ^1_0n

First, the alpha particle is a helium atom. Find the total number of protons and neutrons involved. You'll see you have an extra neutron on your left hand side. There are 2 protons in all on the LHS, and a Helium atom contains that number of protons. You'll see there are 3 neutrons on the LHS, and 2 in the He atom. The extra one is released alone.

Your second question involves deuterium and tritium,

^2_1D + ^3_1T {\rightarrow} {^4_2} \alpha + ^1_0n

First, the alpha particle is a helium atom. Find the total number of protons and neutrons involved. You'll see you have an extra neutron on your left hand side. There are 2 protons in all on the LHS, and a Helium atom contains that number of protons. You'll see there are 3 neutrons on the LHS, and 2 in the He atom. The extra one is released alone.

You'll see there are 3 neutrons on the LHS, and 2 in the He atom. The extra one is released alone.[/QUOTE]

i don't get this part.
or is that the answer for b.?

From mercury to gold? You want to get rich? :joking:

Ok, first, write down the reaction with the unknown particles:

^{200}_{80}Hg {\rightarrow} ^{196}_{79}Au

You'll see that there are 4 neutrons less and a proton less in the gold. If you added a He atom, there would be one extra proton on the RHS. So, add a proton on the left hand side.

^{200}_{80}Hg+ ^1_1p{\rightarrow} ^{196}_{79}Au + ^4_2He

Well, I haven't done nuclear physics yet, but I did some last year. I hope my deductions are good. Anyway, these seem good to me.

i dont get this part.
or is that the answer for b.??

^2_1D

no. of electrons = 1
no. of protons = 1
no. of neutrons = (2-1) = 1

^3_1T

no. of electrons = 1
no. of protons = 1
no. of neutrons = (3-1) = 2

^4_2He

no. of electrons = 2
no. of protons = 2
no. of neutrons = (4-2) = 2

Total neutrons with D and T = 1+2 = 3
Total neutrons with He = 2

Ok? :)

From mercury to gold? You want to get rich? :joking:

Ok, first, write down the reaction with the unknown particles:

^{200}_{80}Hg {\rightarrow} ^{196}_{79}Au

You'll see that there are 4 neutrons less and a proton less in the gold. If you added a He atom, there would be one extra proton on the RHS. So, add a proton on the left hand side.

^{200}_{80}Hg+ ^1_1p{\rightarrow} ^{196}_{79}Au + ^4_2He

Well, I haven't done nuclear physics yet, but I did some last year. I hope my deductions are good. Anyways, these seem good to me.

when the Hg iwht atomic number of 200 adds the proton, does it become 201?

No, it becomes unstable and breaks itself into gold and helium, well, that's what I think.