Solution is found to have a pH of 7.00. What is its pOH?

a. 3.20 b. 7.00
c. 14.00 d. 10.80

[H^+] \times [OH^-] = 10^{-14}

[] = concentration.

pH = -log([H^+])

so if the pH = 7 then [H^+] = 10^{-7}

pOH = -log([OH^-])


Therefore,

pH + pOH = what?