(x+4)^2=16(y+2) find the vertex, focus, and directix of the parabola. Graph the equation. I got the vertex, how do find the focus and directix.

Parabola - Wikipedia, the free encyclopedia (http://en.wikipedia.org/wiki/Parabola) gives you a lot of information about parabolas.

Basically, if you arrange the equation for a parabola in this form:

(x-h)^2=4p(y-k)

or

(y-k)^2=4p(x-h)

The vertex is (x,k); the focus is (h, k+p); the directrix is y=k-p where p is the distance from the vertex to the focus.

Is your equation in this form?

(x+4)^2=16(y+2)

If it is, you should be able to pick out the values directly. The + and/or - signs shouldn't throw you. If you had (x+7)^2, h is simply -7.