Could you please help me to complete this equation , I get the major product but I didn't how to write others.. :confused:



1- Al^3+ + NH4Cl + 3NH4OH... > Al(OH)3 +

2- Ni^2+ + NH4Cl + NH4OH + Na2S... > NiS +

3- Ca^2+ + NH4Cl + NH4OH + (NH4)2CO3... > CaCO3 +

4- Na^+ + Na3Co(NO2)6^3-... >

5- (Solution + glass rod immersed in conc .HCl then on direct flame ) with Ca^2+

6- Pb^2+ + 2HCl... > PbCl2 + (2H^+ or H2)

7- If there is no reaction between two reactants , then when I write the equation it will be the product same as the reactants ?

1. Al^{+3}+ 3OH^- \rightarrow Al(OH)_3

The other ions are spectator ions -- they don't enter into the equation. I'm not sure what the counter-ion was to the Al+3. You can put them in, if you wish, but it really doesn't matter (except possibly to your instructor).

AlCl_3+ 3NH_4OH \rightarrow Al(OH)_3 + 3NH_4Cl

The other problems are done the same way, except #5. I don't get that one.

I think you'll get a red flame... the flame test, you know (btw, I haven't done that at school yet, but this is my bet)

The products are surely CaO and another compound from the anion in the solution.

Calcium does give a red flame. However, the glass rod will emit a yellow flame that will entirely overwhelm the red from the calcium.