I have flow 4gal/min, area 0.7858sqin what is velocity in ft/sec?

V= Q/A = (4gal/min) /0.7854sqin =
V =...

The area is 0.7858 square inches. Convert that to square feet.

0.7858\,in^2\,(\frac {0.00694\,ft^2}{in^2} = 0.00546\,ft^2)

The flow is 4 gallons/minute. Convert that to cubic feet per minute

\large (\frac {4\,gal}{min})(\frac {0.13368
,ft^3}{gal})\,=\,0.535\,\frac {ft^3}{min}

Now, notice how the units work:

\frac {(\frac {ft^3}{min})}{ft^2}\,=\,\frac {ft}{min}

So simply divide

\frac {(\frac {0.535\,ft^3}{min})}{0.00546\,ft^2}\,=\,\frac {97.99\,ft}{min}

It looks like it's darn close to 98 ft/min.

Thank you for your help, but is to late,
My homework is gone, next time please