Can anybody please tell me how to solve the following equation?

k^2 - 8K + 8 = 0

Since it does not factor nicely, use the quadratic formula.

k=-b\pm\frac{\sqrt{b^{2}-4ac}}{2a}

Both solutions are real. Just plug and chug

I assume you know a=1, b=-8, c=8

Can anybody please tell me how to solve the following equation?

k^2 - 8K + 8 = 0



The discriminant (b^2 - 4ac) is positive so both roots are real

Thanks a lot Everyone :)!!